Field theory MOC

Adjoining a root to a field

Let be a field and be a nonzero irreducible polynomial. Then

is a simple extension field of , with primitive element . Moreover, if is a field extension so that has a root in , then we have a tower of field extensions .1 #m/thm/field

Proof

Since is a Euclidean domain and thus in particular a PID. By Maximal ideal iff prime ideal in a PID, it follows is maximal and thus as defined is indeed a field ( for commutative is a field iff is maximal). Let denote the projection. Then

Since all we adjoined was , this is indeed simple.

Now suppose is an extension with , , so the Evaluation map vanishes at , whence and thus by the universal property of quotients there is a unique homomorphism

which gives the desired tower of extensions.


#state/tidy | #lang/en | #SemBr

Footnotes

  1. 2009. Algebra: Chapter 0, §V.5.2, pp. 283–284