Compositions only of algebraic extensions are algebraic
Let
Proof
If
Conversely, suppose
such that
so
is finite. Now
is finite by ^P1 since all the
is finite.
To summarize, we have the tower
where squiggly lines are algebraic and dashed lines are finite.
Finally we see that
must be finite and thus
#state/tidy | #lang/en | #SemBr
Footnotes
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2009. Algebra: Chapter 0, §VII.1.3, p. 395 ↩