𝜑 is injective iff 𝜑(𝑎) =𝜑(𝑏) ⟹ 𝑎 =𝑏 iff 𝜑(𝑎𝑏−1) =𝑒 ⟹ 𝑎𝑏−1 =𝑒 iff ker𝜑 ={𝑒}.
Clearly injective 𝜑 implies monic 𝜑.
Now let 𝜑 :𝐺 ↣𝐻 be a monomorphism.
Let 𝜄 :ker𝜑 ↪𝐺 be the canonical injection and 𝛼𝑇 :ker𝜑 →𝐺 :𝑥 ↦𝑒 be the trivial homomorphism.
Since 𝜑𝜄 =𝜑𝛼𝑇, 𝜄 =𝛼𝑇 and hence ker𝜑 ={𝑒}.