Analysis MOC

Lebesgue number

Let be a compact metric space and be an open cover. Then there exists a Lebesgue number such that every with diameter less than is contained entirely within one of the covering sets, #m/thm/anal i.e.

Proof

Since is an open cover, for every there exists some neighbourhood of , and hence some so that . Then is an open cover, and since is compact there exists some finite subcover where are points in . Then is a Lebesgue number.


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