Field of rational functions

Lower bound on the dimension of the field of rational functions

Let 𝕂 be a field and 𝕂(𝑥) be its field of rational functions in indeterminate 𝑥. Then the 𝕂-dimension of 𝕂(𝑥) is at least the cardinality of 𝕂. #m/thm/ring

|𝕂|dim𝕂𝕂(𝑥)

In particular, the following set linearly independent:

𝑆={1𝑥𝜆:𝜆𝕂}
Proof

Let

𝑓𝑛(𝑥)=𝑝𝑛(𝑥)𝑞𝑛(𝑥)=𝑛𝑖=11𝑥𝜆𝑖

where

𝑞𝑛(𝑥)=𝑛𝑖=1(𝑥𝜆𝑖)

then

𝑓𝑛+1(𝑥)=𝑝𝑛(𝑥)𝑞𝑛(𝑥)+1𝑥𝜆𝑛+1=𝑝𝑛(𝑥)(𝑥𝜆𝑛+1)+𝑞𝑛(𝑥)𝑞𝑛(𝑥)(𝑥𝜆𝑛+1)

which is zero iff 𝑞𝑛(𝑥) = (𝑥 𝜆𝑛+1)𝑝𝑛(𝑥). But this is impossible since (𝑥 𝜆𝑛+1) 𝑞𝑛(𝑥).


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