We define
Ξπ(π)=ππ+1β1πβ1[π,π ]π=β(ππβ1)Let π =GF(π)π+1, so PG(π,π) =P(π).
As a vector space π contains ππ +1 points.
Now the number of points in PG(π,π) equals the number of 1-dimensional subspaces of π,
and different subspaces have only the origin in common.
Thus the number of 1-dimensional subspaces is
ππ+1β1πβ1=Ξπ(π)Each π-dimensional subspace is determined by π +1 linearly independent points,
so the number of π-dimensional subspaces in an π-dimensional projective space is the total number of independent sets of points of size π +1 divided by the number of independent sets of points of size π +1 in each π-dimensional subspace.
This gives
[πβπ+1,π+1]π[1,π+1]πas required.