Orthogonality by a quadric
Let
be the corresponding bilinear form.1
Then for
- Let
be an arbitrary point. Then iff the lineis a secant of , i.e. . - Let
. Then iff the lineis a tangent of at , i.e. . - Let
. Then iff the lineis a line of , i.e. completely contained in .
Proof
#state/tidy | #lang/en | #SemBr
Footnotes
-
2020. Finite geometries, ¶4.50, pp. 104–105 ↩