Projective module
An
This is equivalent to any of the following1
preserves epimorphisms;- Any Module epimorphism
splits; is a direct summand of a free module, i.e. for some moduleand some cardinal ; is exact.
Proof
If ^P1 holds,
then taking
If ^P2 holds, consider an epimorphism
guarantees the required direct sum decomposition, giving ^P3.
Note that
it follows from ^P1 that ^P3 implies ^P4.
Noting that being a module epimorphism is the same as being a regular epimorphism, and that the latter must be preserved by exact functors, it is clear that ^P4 implies ^P3.
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Footnotes
-
2011. Introduction to representation theory, §8.1, pp. 205–332 ↩