Second countability axiom Second countable implies Lindelöf Let be a topological space. If is second-countable then it is Lindelöf. ProofLet be a countable topological basis of , and be an open cover. Let such thatAnd for every let such that . Since every is the union of some family of with , is a countable open cover of and therefore is too. The proof relies on the Axiom of Choice. #state/tidy| #lang/en | #SemBr