Group theory MOC

Centralizer in a group

The centralizer 𝐢𝐺(π‘Ž) of an element π‘Ž ∈𝐺 is a Subgroup of 𝐺 containing all elements that commute with π‘Ž,1 #m/def/group i.e.

𝐢𝐺(π‘Ž)={π‘βˆˆπΊβˆ£π‘Žπ‘=π‘π‘Ž}

More generally, the centralizer 𝐢𝐺(𝑆) of any set 𝑆 βŠ†πΊ contains elements which commute with the whole of 𝑆, i.e.

𝐢𝐺(𝑆)={π‘₯∈𝐺:(βˆ€π‘ βˆˆπ‘†)[π‘₯𝑠=𝑠π‘₯]}
Proof of subgroups

Let π‘Ž ∈𝐺. Clearly 𝑒 ∈𝐢(π‘Ž), Given any 𝑏,𝑐 ∈𝐢(π‘Ž), clearly (𝑏𝑐)π‘Ž =𝑏(π‘π‘Ž) =𝑏(π‘Žπ‘) =(π‘π‘Ž)𝑐 =(π‘Žπ‘)𝑐 =π‘Ž(𝑏𝑐), hence 𝐢(π‘Ž) is closed under the binary operation. Similarly, π‘Žπ‘ =π‘π‘Ž may be both pre- and postmultiplied by π‘βˆ’1 to obtain π‘βˆ’1π‘Ž =π‘Žπ‘βˆ’1, so 𝐢(π‘Ž) is closed under the inverse operation. Hence 𝐢(π‘Ž) is a subgroup of 𝐺 by Two step subgroup test.

Since the intersection of subgroups is a subgroup, 𝐢𝐺(𝑆) =β‹‚π‘ βˆˆπ‘†πΆπΊ(𝑠) must also be a subgroup.

A related notion is the Centre of a group 𝑍(𝐺) =𝐢𝐺(𝐺), which includes only those elements that commute with all group elements.

Additional properties


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Footnotes

  1. 2017, Contemporary Abstract Algebra, p. 68 ↩