Group theory MOC

Subgroup

A subgroup is a subset of a group 𝐻 𝐺 such that 𝐻 is a group under the same operations #m/def/group , i.e. 𝐻 is

Tests for subgroups

Let 𝐺 be a group and 𝐻 𝐺 be a inhabited subset. Additionally we define predicate 𝑝 so that 𝐻 ={𝑥 𝐺 𝑝(𝑥)}. The following hold:1

One step subgroup test

Theorem. Iff 𝑎𝑏1 𝐻 whenever 𝑎,𝑏 𝐻, then 𝐻 is a subgroup of 𝐺. #m/thm/group

Proof

Since 𝐻 is inhabited there exists 𝑥 𝐻, then with 𝑎 =𝑏 =𝑥 clearly 𝑒 𝐻, 𝐻 must be closed under inversion, since letting 𝑎 =𝑒 for any 𝑏 𝐻 we have 𝑒𝑏1 =𝑏1 𝐻. Now we can show that 𝐻 is closed in general: For any 𝑎,𝑏 𝐻 we have 𝑏1 𝐻 and therefore 𝑎𝑏 =𝑎(𝑏1)1 𝐻.

Application
  1. Show 𝑝(𝑒)
  2. Assume 𝑝(𝑎) and 𝑝(𝑏)
  3. Prove 𝑝(𝑎𝑏1)

Two step subgroup test

Theorem. Iff 𝐻 is closed under the binary operation and under the inverse, then 𝐻 is a subgroup of 𝐺. #m/thm/group

Proof

Since 𝐻 is inhabited there exists 𝑥 in 𝐻, thus 𝑥1 𝐻 and thus 𝑒 =𝑥𝑥1 𝐻. Thence 𝐻 is a subgroup of 𝐺.

Application

Much the same as above, but with

  1. Prove 𝑝(𝑎1) and 𝑝(𝑎𝑏).

Finite subgroup test

Theorem. 𝐻 is finite and closed under the binary operation, then it is a subgroup of 𝐺. #m/thm/group

Proof

Take any 𝑥 𝐻. Since 𝐻 is closed we may construct a sequence (𝑥𝑛)𝑛=1 𝐻. Since 𝐻 is finite, by the Pigeonhole principle the sequence must have repeated elements, so that for some 1 <𝑖 <𝑗 we have 𝑥𝑖 =𝑥𝑗. Then 𝑎𝑖𝑗 =𝑒 and hence 𝑎𝑎𝑖𝑗1 =𝑒, so 𝑎1 =𝑎𝑖𝑗1 𝐻. Therefore 𝐻 is closed under the inverse and the binary operation, and is thus a subgroup of 𝐺 by the Two step subgroup test.

Examples of subgroups

Properties


#state/tidy | #lang/en | #SemBr

Footnotes

  1. 2017, Contemporary Abstract Algebra, pp. 62–64