By Schur's lemma, 𝐴𝖬𝗈𝖽(𝑉,𝑉) is a division algebra over 𝕂.
Suppose 𝜗 ∈𝐴𝖬𝗈𝖽(𝑉,𝑉) is transcendental over 𝕂, i.e. 𝑝(𝜗) =0 iff 𝑝 =0 for 𝑝(𝑥) ∈𝕂[𝑥].
The division algebra generated by 𝜗 is then
𝕂(𝜗)={𝑝(𝜗)𝑞(𝜗):𝑝(𝑥),𝑞(𝑥)∈𝕂[𝑥],𝑞≠0}={𝑓(𝜗):𝑓(𝑥)∈𝕂(𝑥)}where 𝕂(𝑥) is the field of rational functions for 𝕂,
and we have a straightforward isomorphism of division 𝕂-algebras 𝕂(𝑥) ≅𝕂(𝜗).
By Lower bound on the dimension of the field of rational functions we have the inequality
|𝕂|≤dim𝕂𝕂(𝑥)=dim𝕂𝕂(𝜗)Since 𝑉 is a vector space over 𝕂(𝜗) with scalar multiplication given by the action of 𝜗, we have
dim𝕂𝕂(𝜗)≤dim𝕂𝑉and thus
|𝕂|≤dim𝕂𝑉a contradiction.