Schur's lemma

Dixmier's lemma

Let 𝐴 be a 𝕂-monoid over 𝕂 and 𝑉 be a simple 𝐴-module. If the cardinality |𝕂| >dim𝕂𝑉, then every 𝐴-module endomorphism 𝜗 𝐴𝖬𝗈𝖽(𝑉,𝑉) is an algebraic element over 𝕂.1 #m/thm/module

Proof

By Schur's lemma, 𝐴𝖬𝗈𝖽(𝑉,𝑉) is a division algebra over 𝕂. Suppose 𝜗 𝐴𝖬𝗈𝖽(𝑉,𝑉) is transcendental over 𝕂, i.e. 𝑝(𝜗) =0 iff 𝑝 =0 for 𝑝(𝑥) 𝕂[𝑥]. The division algebra generated by 𝜗 is then

𝕂(𝜗)={𝑝(𝜗)𝑞(𝜗):𝑝(𝑥),𝑞(𝑥)𝕂[𝑥],𝑞0}={𝑓(𝜗):𝑓(𝑥)𝕂(𝑥)}

where 𝕂(𝑥) is the field of rational functions for 𝕂, and we have a straightforward isomorphism of division 𝕂-algebras 𝕂(𝑥) 𝕂(𝜗). By Lower bound on the dimension of the field of rational functions we have the inequality

|𝕂|dim𝕂𝕂(𝑥)=dim𝕂𝕂(𝜗)

Since 𝑉 is a vector space over 𝕂(𝜗) with scalar multiplication given by the action of 𝜗, we have

dim𝕂𝕂(𝜗)dim𝕂𝑉

and thus

|𝕂|dim𝕂𝑉

a contradiction.


#state/tidy | #lang/en | #SemBr

Footnotes

  1. 1969. On the endomorphism ring of a simple module over an enveloping algebra, p. 171