Five lemma
If the following diagram commutes in
and
Proof
The proof involves proving the two “four lemmata”, by Diagram chasing. We will use additive notation for group operations, but the groups in question need not be abelian.
First we use the fact that
- Let
- By epi
for some - By commutativity
- By exactness
- By mono
- By exactness
- Thus
for some - Thus
- Thus
- By homo
- By exactness
- Thus
for some - By epi
for some - By commutativity
- By homo
Therefore
- Let
, so - By homo
- By commutativity
- By mono
- By exactness
- Thus
for some - By commutativity
- By exactness
- Thus
for some - By epi
for some - By commutativity
- By mono
- By exactness
Therefore
Every Module is a group, and every abelian category has a representation as a module category (Freyd-Mitchell theorem), so the lemma holds for module and abelian categories,
#state/tidy | #lang/en | #SemBr
Footnotes
-
2010, Algebraische Topologie, ¶3.1.10, p.130ff ↩