Krull dimension

Krull dimension of an integral domain

Let be an integral domain. Then the Krull dimension iff is a field, and iff every nonzero prime ideal is maximal.1 #m/thm/ring

Proof

is a field iff it has no nonzero proper ideals. So if is a field, . Conversely, if then is a maximal ideal (as Assuming choice, commutative ring has a maximal ideal and A maximal ideal in a commutative ring is prime), and thus has no nonzero proper ideals: is a field.

Note for every nonzero prime ideal is maximal by vacuity. Given , then any nonzero prime ideal is contained within a maximal ideal which is also prime (since Every ideal in a commutative ring is contained in a maximal ideal), but this must be equal to or else implies .


#state/tidy | #lang/en | #SemBr

Footnotes

  1. 2022. Algebraic number theory course notes, ¶1.23, p. 15