Ring

Peirce decomposition

In a ring 𝑅, let 𝑒 be an idempotent and 𝑓 =(1 𝑒) its complement. Then #m/thm/ring

  1. 𝑅 =𝑅𝑒 𝑅𝑓 as left ideals
  2. 𝑅 =𝑒𝑅 𝑓𝑅 as right ideals;
  3. 𝑅 =𝑒𝑅𝑒 𝑒𝑅𝑓 𝑓𝑅𝑒 𝑓𝑅𝑓 as abelian groups.

In ^D3, we have that 𝑒𝑅𝑒 and 𝑓𝑅𝑓 are in fact subrings, called the corner rings, where

𝑒𝑅𝑒={𝑟𝑅::𝑒𝑟=𝑟=𝑟𝑒}𝑓𝑅𝑓={𝑟𝑅::𝑓𝑟=𝑟=𝑟𝑓}.

These are named after the case where 𝑒 =diag(1,,1,0,,0) in a matrix ring, since then

𝑒𝑅𝑒={[000]},𝑒𝑅𝑓={[000]}𝑓𝑅𝑒={[000]}𝑓𝑅𝑓={[000]}

Properties

  1. 𝑒 is central iff 𝑒𝑅𝑓 =𝑓𝑅𝑒 =0.
Proof

For a given 𝑟 𝑅,

𝑒𝑟𝑓=𝑒𝑟(1𝑒)=𝑒𝑟𝑒𝑟𝑒,𝑓𝑟𝑒=(1𝑒)𝑟𝑒=𝑟𝑒𝑒𝑟𝑒,

so both are zero iff 𝑒𝑟 =𝑒𝑟𝑒 =𝑟𝑒, proving ^P1.


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