Module theory MOC
K-tensor product of modules
Let ๐,๐ be modules over a commutative ring K.
The tensor product ๐ โK๐ is an K-module such that the K-bilinear maps from ๐ ร๐ are in correspondence with the K-linear maps from ๐ โK๐, as defined by the Universal property.1
A generalization for the ๐
-tensor product of modules exists, but is not necessarily a module.
We recover this notion of tensor product as the Tensor product of bimodules.
Universal property
Let ๐,๐ be K-modules.
The tensor product is a pair consisting of an K-module ๐ โK๐ together with an K-bilinear map ( โ) :๐ ร๐ โ๐ โK๐
such any K-bilinear map ๐ :๐ ร๐ โ๐ factorizes uniquely through ( โ) #m/def/module/comm

such that โโ๐ is K-linear.
Construction
Let ๐
(๐ร๐) be the free module on ๐ ร๐ with the natural inclusion function ๐ :๐ ร๐ โช๐
(๐ร๐).
Let ๐พ denote the K-Submodule of ๐
(๐ร๐) generated by elements of the form
๐(๐,๐ผ๐1+๐ฝ๐2)โ๐ผ๐(๐,๐1)โ๐ฝ๐(๐,๐2);๐(๐ผ๐1+๐ฝ๐2,๐)โ๐ผ๐(๐1,๐)โ๐ฝ๐(๐2,๐);
for all ๐,๐1,๐2 โ๐, ๐,๐1,๐2 โ๐, ๐ผ,๐ฝ โ๐
.
We construct the tensor product as the quotient module
๐โK๐=K(๐ร๐)/๐พ
with its natural projection ๐ :K(๐ร๐) โ ๐ โK๐,
so that the map
(โ)=๐โ๐:๐ร๐โ๐โK๐
Proof of the universal property
By construction ( โ) is K-bilinear.
Let ๐ :๐ ร๐ โ๐ be K-bilinear.
By the universal property of the free module we have a unique K-linear map ห๐ such that the following commutes:

and by the K-bilinearity of ๐ it follows ๐พ โค๐
๐ฌ๐๐ฝkerโกห๐,
so by the universal property of the quotient module ห๐ factors uniquely through ๐,
yielding the commutative diagram

as required.
Properties
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