Module theory MOC

Change of ring

Suppose 𝜌 :𝑅 →𝑆 is a ring homomorphism. For any 𝑆-module 𝑉, we have a (left) 𝑅-module πœŒβˆ—π‘‰ by restriction of scalars. Explicitly, πœŒβˆ—π‘‰ is the 𝑅-module with the same underlying abelian group as 𝑉 and the 𝑅-action defined by π‘₯𝑣 =𝜌(π‘₯)𝑣. Since any 𝑆-morphism 𝑉 β†’π‘Š becomes an 𝑅-morphism of πœŒβˆ—π‘‰ β†’πœŒβˆ—π‘Š, we have a β€œforgetful” faithful functor πœŒβˆ— :π‘†π–¬π—ˆπ–½ β†’π‘…π–¬π—ˆπ–½. In fact, this functor has both left and right adjoints, giving us an adjoint triple

c|https://q.uiver.app/#q=WzAsMixbMCwwLCJcXGxNb2QgUiJdLFsyLDAsIlxcbE1vZCBUIl0sWzAsMSwiXFxyaG9fISIsMSx7ImN1cnZlIjotNH1dLFswLDEsIlxccmhvXyoiLDEseyJjdXJ2ZSI6NH1dLFsxLDAsIlxccmhvXioiLDFdLFs0LDMsIiIsMCx7ImxldmVsIjoxLCJzdHlsZSI6eyJuYW1lIjoiYWRqdW5jdGlvbiJ9fV0sWzIsNCwiIiwwLHsibGV2ZWwiOjEsInN0eWxlIjp7Im5hbWUiOiJhZGp1bmN0aW9uIn19XV0=&macro_url=https%3A%2F%2Fraw.githubusercontent.com%2Fjajaperson%2FPKM%2Frefs%2Fheads%2Fmain%2Fpreamble.sty

where

Note that is some cases πœŒβˆ— β‰…πœŒ! are naturally isomorphic: When 𝜌 is a Frobenius extension.

Extension of scalars

Let 𝜌 :𝑅 →𝑆 be a ring homomorphism, and let 𝑆𝑆𝑅 denote 𝑆 regarded as a (𝑆,𝑅)-bimodule, where the right action is given by 𝑠 β—ƒπ‘Ÿ =𝑠 𝜌(π‘Ÿ). We define 𝜌! from the Tensor product of bimodules as the functor

𝜌!:=π‘†π‘†π‘…βŠ—π‘…?.

It follows for an 𝑅-module 𝑉, we have the 𝑆-action

𝑠1(𝑠2βŠ—π‘£)=𝑠1𝑠2βŠ—π‘£

for π‘₯ βˆˆπ‘†, 𝑦 βˆˆπ‘…, and 𝑣 βˆˆπ‘‰. c|https://q.uiver.app/#q=WzAsNSxbMiwwLCJcXHJob14qXFxyaG9fIVYiXSxbNCwwLCJWIl0sWzIsMiwiXFxyaG9eKlciXSxbMCwwLCJcXHJob18hViJdLFswLDIsIlciXSxbMSwwLCJcXGV0YV9WIiwyXSxbMSwyLCJmIl0sWzAsMiwiXFxyaG9eKiBmXlxcc2hhcnAiLDIseyJzdHlsZSI6eyJib2R5Ijp7Im5hbWUiOiJkYXNoZWQifX19XSxbMyw0LCJmXlxcc2hhcnAiLDIseyJzdHlsZSI6eyJib2R5Ijp7Im5hbWUiOiJkYXNoZWQifX19XV0=&macro_url=https%3A%2F%2Fraw.githubusercontent.com%2Fjajaperson%2FPKM%2Frefs%2Fheads%2Fmain%2Fpreamble.sty

The unit of the adjunction 𝜌! βŠ£πœŒβˆ— is the (not necessarily injective) β€œinclusion,” with components

πœ‚π‘‰:π‘‰β†’πœŒβˆ—πœŒ!(𝑉)𝑣↦1βŠ—π‘£.
Proof of adjunction

Suppose π‘Š is a 𝑆-module and 𝑓 :𝑉 β†’πœŒβˆ—π‘Š is an 𝑅-morphism. The right diagram says that for 𝑣 βˆˆπ‘‰,

𝑓(1βŠ—π‘£)=π‘“β™―πœ‚π‘‰(𝑣)=𝑓(𝑣).

which by 𝑆-linearity uniquely defined 𝑓.

CoΓ«xtension of scalars

Let 𝜌 :𝑅 →𝑆 be a ring homomorphism, and let 𝑅𝑆 denote 𝑆 regarded as a left 𝑅-module via the action π‘₯ ▹𝑦 =𝜌(π‘₯)𝑦.

We define the functor πœŒβˆ— :π‘…π–¬π—ˆπ–½ β†’π‘†π–¬π—ˆπ–½ so that

  1. the image πœŒβˆ—π‘‰ of an 𝑅-module 𝑉 is the 𝑆-module with underlying abelian group π‘…π–¬π—ˆπ–½(𝑅𝑆,𝑉) and 𝑆-action 𝑠1 ▹𝑓 =𝑠2 ↦𝑓(𝑠2𝑠1).1
  2. the image πœŒβˆ—π‘“ of an 𝑅-morphism 𝑓 :𝑉 β†’π‘Š is the 𝑆-morphism with underlying group homomorphism π‘…π–¬π—ˆπ–½(𝑅𝑆,𝑔):π‘…π–¬π—ˆπ–½(𝑅𝑆,𝑉)β†’π‘…π–¬π—ˆπ–½(𝑅𝑆,π‘Š)π‘“β†¦π‘”βˆ˜π‘“.
Proof of 𝑆-linearity

To reduce parentheses, the action β–Ή takes precedence over application of functions.

To see that πœŒβˆ—π‘‰ has a valid 𝑆-action: closure follows from

𝑠1▹𝑓(π‘Ÿ1▹𝑠2+π‘Ÿ2▹𝑠3)=𝑠1▹𝑓(𝜌(π‘Ÿ1)𝑠2+𝜌(π‘Ÿ2)𝑠3)=𝑓(𝜌(π‘Ÿ1)𝑠2𝑠1+𝜌(π‘Ÿ2)𝑠3𝑠1)=π‘Ÿ1𝑓(𝑠2𝑠1)+π‘Ÿ2𝑓(𝑠3𝑠1)=π‘Ÿ1(𝑠1▹𝑓)(𝑠2)+π‘Ÿ2(𝑠1▹𝑓)(𝑠3);

unitality follows immediately; multiplicativity follows from

𝑠1𝑠2▹𝑓(𝑠3)=𝑓(𝑠3𝑠1𝑠2)=𝑠2▹𝑓(𝑠3𝑠1)=𝑠1▹𝑠2▹𝑓(𝑠3);

scalar distributivity follows from

𝑠1▹𝑓1+𝑓2(𝑠2)=(𝑓1+𝑓2)(𝑠2𝑠1)=𝑓1(𝑠2𝑠1)+𝑓2(𝑠2𝑠1)=𝑠1▹𝑓1(𝑠2)+𝑠1▹𝑓2(𝑠2)=(𝑠1▹𝑓1+𝑠1▹𝑓2)(𝑠2);

vector distributivity follows from

(𝑠1+𝑠2)▹𝑓(𝑠3)=𝑓(𝑠3(𝑠1+𝑠2))=𝑓(𝑠2𝑠1+𝑠3𝑠2)=𝑓(𝑠2𝑠1)+𝑓(𝑠3𝑠2)=𝑠1▹𝑓(𝑠3)+𝑠2▹𝑓(𝑠1).

That πœŒβˆ—π‘” is well-defined and preserved addition follows from the internal-hom of 𝖠𝖻. To see that πœŒβˆ—π‘” preserves the 𝑆-action,

πœŒβˆ—π‘”(𝑠1▹𝑓)(𝑠2)=π‘”βˆ˜(𝑠1▹𝑓)(𝑠2)=𝑔(𝑓(𝑠2𝑠1))=𝑠1β–Ή(π‘”βˆ˜π‘“)(𝑠2)

as required.

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The coΓΌnit of the adjunction πœŒβˆ— βŠ£πœŒβˆ— is the β€œprojection” with components

πœ–π‘‰:πœŒβˆ—πœŒβˆ—π‘‰β†’π‘‰π‘“β†¦π‘“(1)
Proof of 𝑅-linearity and adjunction

To see that πœ–π‘‰ is 𝑅-linear, it suffices to note

πœ–π‘‰(𝜌(π‘Ÿ)▹𝑓1)=𝜌(π‘Ÿ)▹𝑓(1)=𝑓(𝜌(π‘Ÿ))=π‘Ÿπ‘“(1)=π‘Ÿ1πœ–π‘‰(𝑓)

by the 𝑅-linearity of 𝑓.

Next we show that πœ–π‘‰ is a coΓΌnit of adjunction. Suppose that π‘Š is a 𝑆-module and 𝑓 :πœŒβˆ—π‘Š →𝑉 is an 𝑅-morphism. The left diagram says that for 𝑀 βˆˆπ‘Š we have

𝑓♭(𝑀)(1)=πœ–π‘‰π‘“β™­(𝑀)=𝑓(𝑀)βˆˆπœŒβˆ—π‘‰=π‘…π–¬π—ˆπ–½(𝑅𝑆,𝑉)

This determines the 𝑓♭(𝑀) completely, as for any 𝑠 βˆˆπ‘† we have

𝑓♭(𝑠𝑀)(1)=𝑠▹𝑓♭(𝑀)(1)=𝑓♭(𝑀)(𝑠)

by 𝑆-linearity.


#state/tidy | #lang/en | #SemBr

Footnotes

  1. Crucially, the restricted 𝑅-action on πœŒβˆ—πœŒβˆ—π‘‰ will not be the usual 𝑅-action on π‘…π–¬π—ˆπ–½(𝑅𝑇,𝑉), but instead π‘Ÿ ▹𝑓(𝑑) =π‘Ÿ ▹𝑓(𝑑 𝜌(π‘Ÿ)). ↩