Let ππ ββ[πΊ] be an idempotent.
Then π βπ βππ βππ =π βπ βππ for any π,π ββ[πΊ],
so by associativity Pβ[πΊ](ππ)Ξβ[πΊ](π)Pβ[πΊ](ππ) =Ξβ[πΊ](π)Pβ[πΊ](ππ).
Thus Pβ[πΊ](ππ)β[πΊ] is a left-ideΓ€l with projection operator ππ =Pβ[πΊ](ππ).
Let πΏ be a left ideal and π βπΏ.
The orthogonal complement of an invariant subspace under a unitary operator is invariant,
so we may decompose π =π1 +π2 with π1 βπΏ and π2 βπΏβ.
In particular, the identity π =π1 +π2, so
πβπ=πβπ1ββπΏ+πβπ2ββπΏβso Pβ[πΊ](π1) projects onto πΏ.
Clearly π1 is idempotent since π1 βπ1 =Pβ[πΊ](π1)π1 =π1.